2cos^2(2x)+3cos^2=2

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Solution for 2cos^2(2x)+3cos^2=2 equation:


Simplifying
2cos2(2x) + 3cos2 = 2

Remove parenthesis around (2x)
2cos2 * 2x + 3cos2 = 2

Reorder the terms for easier multiplication:
2 * 2cos2 * x + 3cos2 = 2

Multiply 2 * 2
4cos2 * x + 3cos2 = 2

Multiply cos2 * x
4cos2x + 3cos2 = 2

Reorder the terms:
3cos2 + 4cos2x = 2

Solving
3cos2 + 4cos2x = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Reorder the terms:
-2 + 3cos2 + 4cos2x = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 3cos2 + 4cos2x = 0

The solution to this equation could not be determined.

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